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author | siveshs <siveshs@gmail.com> | 2010-07-02 13:21:36 +0000 |
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committer | bnewbold <bnewbold@adelie.robocracy.org> | 2010-07-02 13:21:36 +0000 |
commit | 7f63506972de44746eb875bdb6e90c7648232be6 (patch) | |
tree | 22aa95727d921e09b16219c399e06b71ed701afa /Fourier Series.page | |
parent | dd41ce0aea48eb532db2292fe072f1119b41942a (diff) | |
download | afterklein-wiki-7f63506972de44746eb875bdb6e90c7648232be6.tar.gz afterklein-wiki-7f63506972de44746eb875bdb6e90c7648232be6.zip |
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Diffstat (limited to 'Fourier Series.page')
-rw-r--r-- | Fourier Series.page | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Fourier Series.page b/Fourier Series.page index d81f78b..9c20925 100644 --- a/Fourier Series.page +++ b/Fourier Series.page @@ -40,7 +40,7 @@ $\qquad\sin^3(x) = \frac{3\sin(x)-\sin(3x)}{4}$ Substituting back in the former equation, we get $$ -\begin{array} +\begin{array} {ccl} \sin(2x) & = & 2\sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}]\\ & = & \frac{1}{2}\sin(x) + \frac{1}{2}\sin(3x)\\ \end{array} |