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| -rw-r--r-- | Fourier Series.page | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Fourier Series.page b/Fourier Series.page index d81f78b..9c20925 100644 --- a/Fourier Series.page +++ b/Fourier Series.page @@ -40,7 +40,7 @@ $\qquad\sin^3(x) = \frac{3\sin(x)-\sin(3x)}{4}$ Substituting back in the former equation, we get $$ -\begin{array} +\begin{array} {ccl} \sin(2x) & = & 2\sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}]\\ & = & \frac{1}{2}\sin(x) + \frac{1}{2}\sin(3x)\\ \end{array} |