From 7f63506972de44746eb875bdb6e90c7648232be6 Mon Sep 17 00:00:00 2001
From: siveshs <siveshs@gmail.com>
Date: Fri, 2 Jul 2010 13:21:36 +0000
Subject: still testing

---
 Fourier Series.page | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

(limited to 'Fourier Series.page')

diff --git a/Fourier Series.page b/Fourier Series.page
index d81f78b..9c20925 100644
--- a/Fourier Series.page	
+++ b/Fourier Series.page	
@@ -40,7 +40,7 @@ $\qquad\sin^3(x) = \frac{3\sin(x)-\sin(3x)}{4}$
 Substituting back in the former equation, we get  
   
 $$
-\begin{array}
+\begin{array} {ccl}
 \sin(2x) & = & 2\sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}]\\ 
 & = & \frac{1}{2}\sin(x) + \frac{1}{2}\sin(3x)\\
 \end{array}
-- 
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