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| -rw-r--r-- | Problem Set 2.page | 3 |
1 files changed, 1 insertions, 2 deletions
diff --git a/Problem Set 2.page b/Problem Set 2.page index cc84acb..05c4885 100644 --- a/Problem Set 2.page +++ b/Problem Set 2.page @@ -54,8 +54,7 @@ $a_{-4} = a_{4} = \sqrt{2\pi} \times 1/16$, $a_{-2} = a_{2} = - \sqrt{2\pi} \tim Since $a_m = < f_m, f >$, - -$\int_0^{2\pi} \sin^4(x) dx = <1, f> = \sqrt{2\pi} \times $<f_0, f>$$ +$ \int_0^{2\pi} \sin^4(x) dx = <1, f> = \sqrt{2\pi} \times <f_0, f>$ $= \sqrt{2\pi} \times a_0 = \frac{3 \pi}{4}$ |