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authorsiveshs <siveshs@gmail.com>2010-07-03 04:54:25 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-03 04:54:25 +0000
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@@ -173,7 +173,7 @@ Due to orthonormality of basis vectors, the inner product in the right-hand side
Thus,
$$ (f, f_m) = a_m $$
Using the definition of the inner product,
-$$ a_m = \int_0^{2\pi} \, f \, \frac{1}{sqrt{2\pi}} \, e^ {-inx} \, dx $$
+$$ a_m = \int_0^{2\pi} \, f \, \frac{1}{\sqrt{2\pi}} \, e^ {-inx} \, dx $$
This is the common definition for the terms of the Fourier series.