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authorsiveshs <siveshs@gmail.com>2010-07-03 04:54:07 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-03 04:54:07 +0000
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section 3 editing
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@@ -167,7 +167,15 @@ $$
(f, f_m) & = & \left( \Sigma a_n\,f_n , f_m \right)\\
& = & \Sigma a_n\,\left(f_n , f_m \right)\\
\end{array}
-$$
+$$
+
+Due to orthonormality of basis vectors, the inner product in the right-hand side of the above equation is $0$ for all terms except $n = m$.
+Thus,
+$$ (f, f_m) = a_m $$
+Using the definition of the inner product,
+$$ a_m = \int_0^{2\pi} \, f \, \frac{1}{sqrt{2\pi}} \, e^ {-inx} \, dx $$
+
+This is the common definition for the terms of the Fourier series.
##Proving that this function is does indeed completely represent $f$