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authorsiveshs <siveshs@gmail.com>2010-07-03 04:49:59 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-03 04:49:59 +0000
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Extending this principle to the case of an n-dimensional vector:
-Let $f$ be the periodic function expressed as $f= \Sigma a_n \frac{1}{\sqrt{2\pi}} \, e^{inx} = \Sigma a_n \, f_n$ where $a_n \in \mathbb C$
+Let $f$ be the periodic function expressed as $f= \Sigma a_n \frac{1}{\sqrt{2\pi}} \, e^{inx} = \Sigma a_n \, f_n$ where $a_n \in \mathbb C$ and $f_n$ are the basis vectors.
+
+Inner product of the vector (in this case the function $f$) with the some basis vector $f_m$ is:
+$$
+\begin{array}{ccl}
+(f, f_m) & = & \left( \Sigma a_n\,f_n , f_m \right)\\
+& = & \Sigma a_n\,\left(f_n , f_m \right)\\
+
##Proving that this function is does indeed completely represent $f$