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authorsiveshs <siveshs@gmail.com>2010-07-03 04:49:59 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-03 04:49:59 +0000
commitc4a2bf1158888668f27faa7c0de0a7d8264a2057 (patch)
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parent640784256be7ef84a0c59b6981c9ad0439361e28 (diff)
downloadafterklein-wiki-c4a2bf1158888668f27faa7c0de0a7d8264a2057.tar.gz
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section 3 editing
-rw-r--r--Fourier Series.page9
1 files changed, 8 insertions, 1 deletions
diff --git a/Fourier Series.page b/Fourier Series.page
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--- a/Fourier Series.page
+++ b/Fourier Series.page
@@ -159,7 +159,14 @@ $$
Extending this principle to the case of an n-dimensional vector:
-Let $f$ be the periodic function expressed as $f= \Sigma a_n \frac{1}{\sqrt{2\pi}} \, e^{inx} = \Sigma a_n \, f_n$ where $a_n \in \mathbb C$
+Let $f$ be the periodic function expressed as $f= \Sigma a_n \frac{1}{\sqrt{2\pi}} \, e^{inx} = \Sigma a_n \, f_n$ where $a_n \in \mathbb C$ and $f_n$ are the basis vectors.
+
+Inner product of the vector (in this case the function $f$) with the some basis vector $f_m$ is:
+$$
+\begin{array}{ccl}
+(f, f_m) & = & \left( \Sigma a_n\,f_n , f_m \right)\\
+& = & \Sigma a_n\,\left(f_n , f_m \right)\\
+
##Proving that this function is does indeed completely represent $f$