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-rw-r--r--physics/quantum/fermigas11
1 files changed, 5 insertions, 6 deletions
 diff --git a/physics/quantum/fermigas b/physics/quantum/fermigasindex b91c67c..0114b43 100644--- a/physics/quantum/fermigas+++ b/physics/quantum/fermigas@@ -39,14 +39,13 @@ correction can be important. There will then be a second correction due to removing the states along the individual axes twice (once for each side-surface), u.s.w. -The surface of this shell is called the Fermi surface-and represents the most excited states in the gas. The radius can be derived-by calculating the total volume enclosed: each block has volume -:m:$\frac{\pi^3}{l_x l_y l_z}=\frac{pi^3}{V}$ and there are N/2 blocks occupied by N -fermions, so:+The surface of this shell is called the Fermi surface and represents the most+excited states in the gas. The radius can be derived by calculating the total+volume enclosed: each block has volume :m:$\frac{\pi^3}{l_x l_y+l_z}=\frac{\pi^3}{V}$ and there are N/2 blocks occupied by N fermions, so: :m:$$\frac{1}{8}(\frac{4\pi}{3} |k_{F}|^{3})&=&\frac{Nq}{2}(\frac{\pi^{3}}{V})\\|k_{F}|&=&\sqrt{\frac{3Nq\pi^2}{V}}^3=\sqrt{3\pi^2\rho}^3$$ :m:$\rho$ is the "free fermion density". The corresponding energy is: -:m:$$E_{F}=\frac{\hbar^{2}}{2m}|k_{F}|^{2}=\frac{\hbar^{2}}{2m}\sqrt{3\rho \pi}^3$$+:m:$$E_{F}=\frac{\hbar^{2}}{2m}|k_{F}|^{2}=\frac{\hbar^{2}}{2m}(3\rho \pi)^{2/3}$$