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| -rw-r--r-- | Fourier Series.page | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Fourier Series.page b/Fourier Series.page index 984f3e6..4ece8ea 100644 --- a/Fourier Series.page +++ b/Fourier Series.page @@ -38,7 +38,7 @@ Rearranging, $\qquad\sin^3(x) = \frac{3\sin(x)-\sin(3x)}{4}$ Substituting back in the former equation, we get -$\sin(2x).\cos(x) = 2 \sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}] $ +$\sin(2x).\cos(x) = 2 \sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}]$ ##What is the Fourier series actually?</b> |