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| author | siveshs <siveshs@gmail.com> | 2010-07-02 18:40:29 +0000 |
|---|---|---|
| committer | bnewbold <bnewbold@adelie.robocracy.org> | 2010-07-02 18:40:29 +0000 |
| commit | de7c96db371ed8b1450578b1d2717569232388cd (patch) | |
| tree | f22703a2fb7e50484f5e7c514dd0b8a3566c9e23 /Fourier Series.page | |
| parent | d7c253489b5c6df8fb7309fde74ca12d5cba8590 (diff) | |
| download | afterklein-wiki-de7c96db371ed8b1450578b1d2717569232388cd.tar.gz afterklein-wiki-de7c96db371ed8b1450578b1d2717569232388cd.zip | |
still testing
Diffstat (limited to 'Fourier Series.page')
| -rw-r--r-- | Fourier Series.page | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/Fourier Series.page b/Fourier Series.page index 2456aad..6c9d563 100644 --- a/Fourier Series.page +++ b/Fourier Series.page @@ -9,11 +9,11 @@ $1.\quad\sin^2(x) = ?$ Based on the double angle formula, -$\qquad\cos(2x) = 1 - 2 \sin^2(x)$ +$$\cos(2x) = 1 - 2 \sin^2(x)$$ Rearranging, -$\qquad\sin^2(x) = \frac{1-\cos(2x)}{2}$ +$$\sin^2(x) = \frac{1-\cos(2x)}{2}$$ $2.\quad\sin(2x)\cdot\cos(2x) = ?$ |