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authorluccul <luccul@gmail.com>2010-07-04 19:56:22 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-04 19:56:22 +0000
commit9fad491e48138c15f7edb8547f14d19af5b89bb1 (patch)
treef9d4f23d2c95ce0a7272b77622a6380b5d941ff0
parent3f8b5e12eb198dd28960cd8b725c315ab69733bf (diff)
downloadafterklein-wiki-9fad491e48138c15f7edb8547f14d19af5b89bb1.tar.gz
afterklein-wiki-9fad491e48138c15f7edb8547f14d19af5b89bb1.zip
more formatting/editing
-rw-r--r--Problem Set 2.page10
1 files changed, 6 insertions, 4 deletions
diff --git a/Problem Set 2.page b/Problem Set 2.page
index b1b82a5..4fe7a1f 100644
--- a/Problem Set 2.page
+++ b/Problem Set 2.page
@@ -69,13 +69,15 @@ $$\begin{array}{ccl} a_m &=& \frac{1}{\sqrt 2\pi} \int_0^{2\pi} \sin^2(x) e^{-im
&=& \frac{1}{\sqrt 2\pi} \int_0^{2\pi} \frac{e^{-i (m-2)x}+e^{-i (m+2)x}-2e^{-imx}}{4} dx. \end{array} $$
-Because $\int_0^{2\pi} e^{inx} dx = 2\pi$ for $n = 0$ and $\int_0^{2\pi} e^{inx} dx = 0$ for $n \neq 0$,
+Because $\int_0^{2\pi} e^{inx} dx = 2\pi$ for $n = 0$ and $\int_0^{2\pi} e^{inx} dx = 0$ for $n \neq 0$, we have
-$$m = 2 : a_m = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \sqrt{2\pi}/4,$$
+$$a_2 = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \sqrt{2\pi}/4,$$
-$$m = 0 : a_m = \frac{1}{4 \sqrt{2\pi}} \times 2\pi \times (-2) = - \frac{\sqrt{2\pi}{2},$$
+$$a_0 = \frac{1}{4 \sqrt{2\pi}} \times 2\pi \times (-2) = - \frac{\sqrt{2\pi}}{2},$$
-$$m = -2 : a_m = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \frac{\sqrt{2\pi}}{4},$$
+and
+
+$$a_{-2} = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \frac{\sqrt{2\pi}}{4}.$$
It follows that