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authorOpheliar99 <>2010-07-04 02:21:52 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-04 02:21:52 +0000
commit3ceb2d9901fb49cb0a12828dc2fc45e410ca886f (patch)
tree1931048c53dd536296dd6d1b4a508e70383f114b
parent32e82967016f48f091427bc4f57706aba5194d01 (diff)
downloadafterklein-wiki-3ceb2d9901fb49cb0a12828dc2fc45e410ca886f.tar.gz
afterklein-wiki-3ceb2d9901fb49cb0a12828dc2fc45e410ca886f.zip
posted solutions of 2 and 3 in pset2
-rw-r--r--Problem Set 2.page2
1 files changed, 1 insertions, 1 deletions
diff --git a/Problem Set 2.page b/Problem Set 2.page
index 1672b23..4811096 100644
--- a/Problem Set 2.page
+++ b/Problem Set 2.page
@@ -40,7 +40,7 @@ $\int_0^{2\pi} |\sin^2(x)|^2 dx = \sum |a_n|^2.$
2. Since
$\sin x = \frac{e^{ix}-e^{-ix}}{2}$,
-$\int_0^{2\pi} \sin^4(x) dx = \frac{(\left e^{ix}-e^{-ix})}^{4}}{16}$,
+$\int_0^{2\pi} \sin^4(x) dx = \frac{{( e^{ix}-e^{-ix})}^{4}}{16}$,
$ = \frac{e^{i 4x}+e^{-i 4x}-4 e^{i 2x} -4 e^{-i 2x}+6}{16}$.