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authorsiveshs <siveshs@gmail.com>2010-07-02 03:25:18 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-02 03:25:18 +0000
commit314d9975bcc659f1a46d82acba50ace43cf8b240 (patch)
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parent99524349daae12733b5d48fb220c1d5b551219c6 (diff)
downloadafterklein-wiki-314d9975bcc659f1a46d82acba50ace43cf8b240.tar.gz
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still testing
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@@ -7,10 +7,10 @@ To show that Fourier series is plausible, let us consider some arbitrary trignom
$1. \cos(2x) = 1 - 2 \sin^2(x)$
$$\begin{array}{ccl}
-e^{iy} & = 1+iy+\frac{(iy)^{2}}{2!}+\frac{(iy)^{3}}{3!}+\frac{(iy)^{4}}{4!}+\frac{(iy)^{5}}{5!}+\cdots\\
- & = 1+iy-\frac{y^{2}}{2!}-i\frac{y^{3}}{3!}+\frac{y^{4}}{4!}+i\frac{y^{5}}{5!}+\cdots\\
- & = (1-\frac{y^{2}}{2!}+\frac{y^{4}}{4!}+\cdots)+i(y-\frac{y^{3}}{3!}+\frac{y^{5}}{5!}-\cdots)\\
- & = \cos y+i\sin y\end{array}$$
+e^{iy} & = & 1+iy+\frac{(iy)^{2}}{2!}+\frac{(iy)^{3}}{3!}+\frac{(iy)^{4}}{4!}+\frac{(iy)^{5}}{5!}+\cdots\\
+ & = & 1+iy-\frac{y^{2}}{2!}-i\frac{y^{3}}{3!}+\frac{y^{4}}{4!}+i\frac{y^{5}}{5!}+\cdots\\
+ & = & (1-\frac{y^{2}}{2!}+\frac{y^{4}}{4!}+\cdots)+i(y-\frac{y^{3}}{3!}+\frac{y^{5}}{5!}-\cdots)\\
+ & = & \cos y+i\sin y\end{array}$$
##What is the Fourier series actually?</b>