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-rw-r--r--ClassJune26.page8
1 files changed, 3 insertions, 5 deletions
diff --git a/ClassJune26.page b/ClassJune26.page
index 5267204..fb826d9 100644
--- a/ClassJune26.page
+++ b/ClassJune26.page
@@ -189,10 +189,8 @@ curve $\gamma$ through $z$ to a smooth curve $f\circ\gamma$ through
$f(z)$. What happens to the tangent of $\gamma$ at $z$? Given by
the derivative $df(z)$, a linear map taking vectors based at $z$
to vectors based at $f(z)$. If we use rectangular coordinates
- $z\mapsto f(z)$
-
- $x+iy\mapsto u(x,y)+iv(x,y)$
-
+ $z\mapsto f(z)$
+ $x+iy \mapsto u(x,y)+iv(x,y)$
$\left(\begin{array}{c}
x\\
y\end{array}\right)\mapsto\left(\begin{array}{c}
@@ -231,7 +229,7 @@ ie, it looks just like multiplication by the complex number $a+bi$.
The function $f$ is conformal if its derivative acts like a nonzero
complex number. Analytically, this condition is given by the following
differential equations, called the **Cauchy-Riemann equations**:
-$\frac{\partial u}{\partial x}=\frac{\partial v}{\partial y}\mbox{ and }\frac{\partial u}{\partial y}=-\frac{\partial v}{\partial x}.$
+$\frac{\partial u}{\partial x}=\frac{\partial v}{\partial y}\mbox{ and }\frac{\partial u}{\partial y}=-\frac{\partial v}{\partial x}.$
A complex function $f=u+iv$ is said to be **holomorphic** if
$f$ satisfies the CR. We've shown that conformal $\Longrightarrow$
holomorphic. Holomorphic functions are slightly more general, as the