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authorOpheliar99 <>2010-07-04 04:31:03 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-04 04:31:03 +0000
commitd406b157e8e83ef13288d6bce42e1ecf6f1f4cb6 (patch)
tree2fab570cc458bb11d723aabbf30873c9a24f7abc /Problem Set 2.page
parent9c223d0261fd2975b1d0a8ec60718d85bf683224 (diff)
downloadafterklein-wiki-d406b157e8e83ef13288d6bce42e1ecf6f1f4cb6.tar.gz
afterklein-wiki-d406b157e8e83ef13288d6bce42e1ecf6f1f4cb6.zip
posted solutions of 2 and 3 in pset2
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@@ -44,7 +44,7 @@ $\sin x = \frac{e^{ix}-e^{-ix}}{2}$,
$\sin^4 x = \frac{{( e^{ix}-e^{-ix} )}^4}{16}$
$= \frac{e^{i 4x}+e^{-i 4x}-4 e^{i 2x} -4 e^{-i 2x}+6}{16}$.
-//
+
If we express any periodic function $f(x)$ as
$f(x) = \sum a_n f_n(x)$, where $f_n(x) = \frac{e^{inx}}{\sqrt{2\pi}}$ and $f_0(x) = \frac{1}{\sqrt{2\pi}}$,