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| author | Opheliar99 <> | 2010-07-04 04:57:02 +0000 |
|---|---|---|
| committer | bnewbold <bnewbold@adelie.robocracy.org> | 2010-07-04 04:57:02 +0000 |
| commit | d18882b76339230566361b2a402bc5f543da6675 (patch) | |
| tree | 882944cc902bf2c4d7fc6b8a30a2f49c35c17aaf /Problem Set 2.page | |
| parent | 27194cc662f73877a413955c4c5f01761e2c8b08 (diff) | |
| download | afterklein-wiki-d18882b76339230566361b2a402bc5f543da6675.tar.gz afterklein-wiki-d18882b76339230566361b2a402bc5f543da6675.zip | |
posted solutions of 2 and 3 in pset2
Diffstat (limited to 'Problem Set 2.page')
| -rw-r--r-- | Problem Set 2.page | 3 |
1 files changed, 2 insertions, 1 deletions
diff --git a/Problem Set 2.page b/Problem Set 2.page index 1cbcce1..06528fc 100644 --- a/Problem Set 2.page +++ b/Problem Set 2.page @@ -85,7 +85,8 @@ $m = -2 : a_m = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \sqrt{2\pi}/4$, Then, -$\sum |a_n|^2 = {\sqrt{2\pi}/4}^2 + {- \sqrt{2\pi}/2}^2 + {\sqrt{2\pi}/4}^2 = \frac{3 \pi}{4}$ +$\sum |a_n|^2 = {\sqrt{2\pi}/4}^2 + {- \sqrt{2\pi}/2}^2 + {\sqrt{2\pi}/4}^2 = \frac{3 \pi}{4}$. + And, it was shown in Prob 2 that $\int_0^{2\pi} \sin^4(x) dx = \frac{3 \pi}{4}$. Therefore, |