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| author | Opheliar99 <> | 2010-07-04 04:16:56 +0000 |
|---|---|---|
| committer | bnewbold <bnewbold@adelie.robocracy.org> | 2010-07-04 04:16:56 +0000 |
| commit | 60d31ba77b860e5f788fb97fb87d44043288a27e (patch) | |
| tree | 3f7f717143653141a1ebb783b16630c19d7ea966 /Problem Set 2.page | |
| parent | f0c461bce6678793f61c2e0c7fafd8b1801129f6 (diff) | |
| download | afterklein-wiki-60d31ba77b860e5f788fb97fb87d44043288a27e.tar.gz afterklein-wiki-60d31ba77b860e5f788fb97fb87d44043288a27e.zip | |
posted solutions of 2 and 3 in pset2
Diffstat (limited to 'Problem Set 2.page')
| -rw-r--r-- | Problem Set 2.page | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Problem Set 2.page b/Problem Set 2.page index 667abad..de38296 100644 --- a/Problem Set 2.page +++ b/Problem Set 2.page @@ -54,7 +54,7 @@ The Fourier coefficients for the above functions are: $a_{-4} = a_{4} = \sqrt{2\pi} \times 1/16$, $a_{-2} = a_{2} = - \sqrt{2\pi} \times 4/16$, $a_0 = \sqrt{2\pi} \times 6/16$ -Since $a_m = < f_m, f >$, +Since $a_m = < f_m, f >$ and setting $f(x) = \sin^4(x)$, $\int_0^{2\pi} \sin^4(x) dx = <1, f> = \sqrt{2\pi} \times < f_0, f >$ |