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authorjoshuab <>2010-06-30 20:20:30 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-06-30 20:20:30 +0000
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trying to fix integrals
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@@ -29,6 +29,6 @@ $\int_0^{2\pi} \sin^4(x) dx = \frac{3 \pi}{4} $
(Hint: write out the exponential fourier expansion of $\sin^4(x)$.)
3. Compute the exponential Fourier coefficients of $\sin^2(x)$:
-$a_n = \frac{1}{\sqrt(2\pi)} \int_0^{2\pi} sin^2(x) e^{-inx} dx $
+$a_n = \frac{1}{\sqrt(2\pi)} \int_0^{2\pi} sin^2(x) e^{-inx} dx$
and use this to show that
-$\int_0^{2\pi} |\sin^2(x)|^2 dx = \sum |a_n|^2 $
+$\int_0^{2\pi} |\sin^2(x)|^2 dx = \sum |a_n|^2$