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authorbnewbold <bnewbold@alum.mit.edu>2010-06-30 06:34:12 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-06-30 06:34:12 +0000
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@@ -162,8 +162,8 @@ and add them up just fine, so we can exponentiate complex values of
$z$. We know what happens to real values, what happens to pure imaginary
ones? Let $y\in\mathbb{R}$. Then
-$$\begin{array}{ccc}
-ee^{iy} & = & 1+iy+\frac{(iy)^{2}}{2!}+\frac{(iy)^{3}}{3!}+\frac{(iy)^{4}}{4!}+\frac{(iy)^{5}}{5!}+\cdots\\
+$$\begin{array}{ccl}
+e^{iy} & = & 1+iy+\frac{(iy)^{2}}{2!}+\frac{(iy)^{3}}{3!}+\frac{(iy)^{4}}{4!}+\frac{(iy)^{5}}{5!}+\cdots\\
& = & 1+iy-\frac{y^{2}}{2!}-i\frac{y^{3}}{3!}+\frac{y^{4}}{4!}+i\frac{y^{5}}{5!}+\cdots\\
& = & (1-\frac{y^{2}}{2!}+\frac{y^{4}}{4!}+\cdots)+i(y-\frac{y^{3}}{3!}+\frac{y^{5}}{5!}-\cdots)\\
& = & \cos y+i\sin y\end{array}$$
@@ -219,7 +219,7 @@ means that $\left(\begin{array}{c}
\frac{\partial u}{\partial y}\end{array}\right)$ is $\left(\begin{array}{c}
\frac{\partial u}{\partial x}\\
\frac{\partial v}{\partial x}\end{array}\right)$ rotated by $\pi/2$. If we write
-$\[\left(\begin{array}{c}
+$\left(\begin{array}{c}
a\\
b\end{array}\right)=\left(\begin{array}{c}
\frac{\partial u}{\partial x}\\