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-.. highlight:: cpp
-
-.. _lang-compoundbitwise:
-
-Compound Bitwise Operators (``&=``, ``|=``, ``^=``)
-===================================================
-
-The compound bitwise operators perform their calculations at the
-bit level of variables. They are often used to clear and set
-specific bits of a variable.
-
-See the :ref:`bitwise math tutorial <lang-bitwisemath>` for more
-information on bitwise operators.
-
-.. contents:: Contents
- :local:
-
-.. _lang-compoundbitwise-and:
-
-Compound bitwise AND (``&=``)
------------------------------
-
-The compound bitwise AND operator ``&=`` is often used with a variable
-and a constant to force particular bits in a variable to be zero. This
-is often referred to in programming guides as "clearing" or
-"resetting" bits. In a program, writing the line ``x &= y;`` is
-equivalent to writing ``x = x & y;``. That is, the value of ``x``
-after the line will be equal to its old value bitwise ANDed with the
-value of ``y``::
-
- x &= y; // equivalent to x = x & y;
-
-You can use any integer variable for ``x`` (i.e., any variable of type
-``int``, ``char``, ``byte``, ``long long``, etc.). You can use either
-an integer variable or any :ref:`integer value
-<lang-constants-integers>` (like ``3`` or ``0x20``) for ``y``.
-
-Before doing an example of ``&=``, let's first review the Bitwise AND
-(``&``) operator::
-
- 0 0 1 1 operand1
- 0 1 0 1 operand2
- ----------
- 0 0 0 1 (operand1 & operand2) = result
-
-As shown above, bits that are "bitwise ANDed" with 0 become 0, while
-bits that are "bitwise ANDed" with 1 are left unchanged. So, if ``b``
-is a ``byte`` variable, then ``b & B00000000`` equals zero, and ``b &
-B11111111`` equals ``b``.
-
-.. _lang-compoundbitwise-binconst:
-
-.. note:: The above uses :ref:`binary constants
- <lang-constants-integers-bin>`\ . The numbers are still the same
- value in other representations, they just might not be as easy to
- understand.
-
- Normally, in C and C++ code, :ref:`hexadecimal
- <lang-constants-integers-hex>` or :ref:`octal
- <lang-constants-integers-oct>` are used when we're interested in
- an integer's bits, rather than its value as a number.
-
- While hexadecimal and octal literals might be harder to understand
- at first, you should really take the time to learn them. They're
- part of C, C++, and many other programming languages, while binary
- constants are available only for compatibility with Arduino.
-
- Also, ``B00000000`` is shown for clarity, but zero in any number
- format is zero.
-
-So, to clear (set to zero) bits 0 and 1 of a one-byte variable, while
-leaving the rest of the variable's bits unchanged, use the compound
-bitwise AND operator ``&=`` with the constant ``B11111100``
-(hexadecimal ``0xFC``\ )::
-
- 1 0 1 0 1 0 1 0 variable
- 1 1 1 1 1 1 0 0 mask
- ----------------------
- 1 0 1 0 1 0 0 0
- ^^^^^^^^^^^^^^^^ ^^^^
- unchanged cleared
-
-
-Here is the same representation with the variable's bits replaced
-with the symbol ``x``\ ::
-
- x x x x x x x x variable
- 1 1 1 1 1 1 0 0 mask
- ----------------------
- x x x x x x 0 0
- ^^^^^^^^^^^^^^^^ ^^^^
- unchanged cleared
-
-
-So, using a byte variable ``b``\ , if we say::
-
- b = B10101010; // B10101010 == 0xAA
- b &= B11111100; // B11111100 == 0xFC
-
-then we will have ::
-
- b == B10101000; // B10101000 == 0xA8
-
-.. _lang-compoundbitwise-or:
-
-Compound bitwise OR (``|=``)
-----------------------------
-
-The compound bitwise OR operator ``|=`` is often used with a variable
-and a constant to "set" (set to 1) particular bits in a variable. In
-a program, writing the line ``x |= y;`` is equivalent to writing ``x =
-x | y;``. That is, the value of ``x`` after the line will be equal to
-its old value bitwise ORed with the value of ``y``::
-
- x |= y; // equivalent to x = x | y;
-
-You can use any integer variable for ``x`` (i.e., any variable of type
-``int``, ``char``, ``long long`` etc.). You can use either an integer
-variable or any integer value (like ``3`` or ``0x20``) for ``y``.
-(This works the same way as :ref:`compound bitwise AND
-<lang-compoundbitwise-and>`\ , ``&=``).
-
-Before doing an example of ``|=``, let's first review the Bitwise OR
-(``|``) operator::
-
- 0 0 1 1 operand1
- 0 1 0 1 operand2
- ----------
- 0 1 1 1 (operand1 | operand2) = result
-
-Bits that are "bitwise ORed" with 0 are unchanged, while bits that are
-"bitwise ORed" with 1 are set to 1. So if ``b`` is a ``byte``
-variable, then ``b | B00000000`` equals ``b``, and ``b & B11111111``
-equals ``B11111111`` (here we've used binary constants; see the
-:ref:`note <lang-compoundbitwise-binconst>` above).
-
-So, to set bits 0 and 1 of a one-byte variable, while leaving the rest
-of the variable unchanged, use the compound bitwise OR operator
-(``|=``) with the constant ``B00000011`` (hexadecimal ``0x3``)::
-
- 1 0 1 0 1 0 1 0 variable
- 0 0 0 0 0 0 1 1 mask
- ----------------------
- 1 0 1 0 1 0 1 1
- ^^^^^^^^^^^^^^^^ ^^^^
- unchanged set
-
-Here is the same representation with the variable's bits replaced with
-the symbol ``x``::
-
- x x x x x x x x variable
- 0 0 0 0 0 0 1 1 mask
- ----------------------
- x x x x x x 1 1
- ^^^^^^^^^^^^^^^^ ^^^^
- unchanged set
-
-So, using a byte variable ``b``, if we say::
-
- b = B10101010; // B10101010 == 0xAA
- b |= B00000011; // B00000011 == 0x3
-
-then we will have ::
-
- b == B10101011; // B10101011 == 0xAB
-
-.. _lang-compoundbitwise-xor:
-
-Compound bitwise XOR (``^=``)
------------------------------
-
-The compound bitwise XOR operator ``^=`` is used with a variable and a
-constant to "toggle" (change 0 to 1, and 1 to 0) particular bits in a
-variable. In a program, writing the line ``x ^= y;`` is equivalent to
-writing ``x = x ^ y;``. That is, the value of ``x`` after the line
-will be equal to its old value bitwise XORed with the value of ``y``::
-
- x ^= y; // equivalent to x = x ^ y;
-
-You can use any integer variable for ``x`` (i.e., any variable of type
-``int``, ``char``, ``long long``, etc.). You can use either an
-integer variable or any integer value (like ``3`` or ``0x20``) for
-``y``. (This works the same way as :ref:`&=
-<lang-compoundbitwise-and>` and :ref:`\|= <lang-compoundbitwise-or>`;
-in fact, these three operators all work the same in this way).
-
-Before doing an example of ``^=``, let's first review the Bitwise
-XOR operator, ``^``::
-
- 0 0 1 1 operand1
- 0 1 0 1 operand2
- ----------
- 0 1 1 0 (operand1 ^ operand2) = result
-
-One way to look at bitwise XOR is that each bit in the result is a 1
-if the input bits are different, or 0 if they are the same. Another
-way to think about it is that the result bit will be 1 when *exactly*
-one (no more, no less) of the input bits is 1; otherwise, it will be
-zero. This means that if you XOR a bit with 1, it will change (or
-toggle) its value, while if you XOR a bit with 0, it stays the same.
-
-So, to toggle bits 0 and 1 of a one-byte variable, while leaving the
-rest of the variable unchanged, use the compound bitwise XOR operator
-``^=`` with the constant ``B00000011`` (hexadecimal ``0x3``\ ; see
-:ref:`note <lang-compoundbitwise-binconst>` above)::
-
- 1 0 1 0 1 0 1 0 variable
- 0 0 0 0 0 0 1 1 mask
- ----------------------
- 1 0 1 0 1 0 1 1
- ^^^^^^^^^^^^^^^^ ^^^^
- unchanged toggled
-
-So, using a byte variable ``b``, if we say::
-
- b = B10101010; // B10101010 == 0xAA
- b ^= B00000011; // B00000011 == 0x3
-
-then we will have ::
-
- b == B10101001; // B10101001 == 0xA9
-
-See Also
---------
-
-- :ref:`Boolean operations <lang-boolean>` (``&&``, ``||``)
-- :ref:`Bitwise operators <lang-bitwisemath>` (``&``, ``|``, ``^``, ``~``)
-
-.. include:: cc-attribution.txt