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;;; "MISCIO" Search for string from port.
; Written 1995, 1996 by Oleg Kiselyov (oleg@acm.org)
; Modified 1996, 1997, 1998, 2001 by A. Jaffer (agj@alum.mit.edu)
; Modified 2003 by Steve VanDevender (stevev@hexadecimal.uoregon.edu)
;
; This code is in the public domain.
;;;@ Return the index of the first occurence of chr in str, or #f
(define (string-index str chr)
(define len (string-length str))
(do ((pos 0 (+ 1 pos)))
((or (>= pos len) (char=? chr (string-ref str pos)))
(and (< pos len) pos))))
;@
(define (string-index-ci str chr)
(define len (string-length str))
(do ((pos 0 (+ 1 pos)))
((or (>= pos len) (char-ci=? chr (string-ref str pos)))
(and (< pos len) pos))))
;@
(define (string-reverse-index str chr)
(do ((pos (+ -1 (string-length str)) (+ -1 pos)))
((or (negative? pos) (char=? (string-ref str pos) chr))
(and (not (negative? pos)) pos))))
;@
(define (string-reverse-index-ci str chr)
(do ((pos (+ -1 (string-length str)) (+ -1 pos)))
((or (negative? pos) (char-ci=? (string-ref str pos) chr))
(and (not (negative? pos)) pos))))
;@
(define (substring? pat str)
(define patlen (string-length pat))
(define strlen (string-length str))
(cond ((zero? patlen) 0) ; trivial match
((>= patlen strlen) (and (= patlen strlen) (string=? pat str) 0))
;; use faster string-index to match a single-character pattern
((= 1 patlen) (string-index str (string-ref pat 0)))
((or (<= strlen (+ patlen patlen (quotient char-code-limit 2)))
(<= patlen 4))
(subloop pat patlen str strlen char=?))
(else
;; compute skip values for search pattern characters
;; for all c not in pat, skip[c] = patlen + 1
;; for c in pat, skip[c] is distance of rightmost occurrence
;; of c from end of str
(let ((skip (make-vector char-code-limit (+ patlen 1))))
(do ((i 0 (+ i 1)))
((= i patlen))
(vector-set! skip (char->integer (string-ref pat i))
(- patlen i)))
(subskip skip pat patlen str strlen char=?)))))
;@
(define (substring-ci? pat str)
(define patlen (string-length pat))
(define strlen (string-length str))
(cond ((zero? patlen) 0) ; trivial match
((>= patlen strlen) (and (= patlen strlen) (string-ci=? pat str) 0))
((= 1 patlen) (string-index-ci str (string-ref pat 0)))
((or (<= strlen (+ patlen patlen (quotient char-code-limit 2)))
(<= patlen 4))
(subloop pat patlen str strlen char-ci=?))
(else
(let ((skip (make-vector char-code-limit (+ patlen 1))))
(do ((i 0 (+ i 1)))
((= i patlen))
(let ((c (string-ref pat i))
(d (- patlen i)))
;; use same skip value for both upper- and lowercase characters
(vector-set! skip (char->integer (char-upcase c)) d)
(vector-set! skip (char->integer (char-downcase c)) d)))
(subskip skip pat patlen str strlen char-ci=?)))))
(define (subskip skip pat patlen str strlen char=)
(do ((k patlen (if (< k strlen)
(+ k (vector-ref skip (char->integer (string-ref str k))))
(+ strlen 1))))
((or (> k strlen)
(do ((i 0 (+ i 1))
(j (- k patlen) (+ j 1)))
((or (= i patlen)
(not (char= (string-ref pat i) (string-ref str j))))
(= i patlen))))
(and (<= k strlen) (- k patlen)))))
;;; Assumes that PATLEN > 1
(define (subloop pat patlen str strlen char=)
(define span (- strlen patlen))
(define c1 (string-ref pat 0))
(define c2 (string-ref pat 1))
(let outer ((pos 0))
(cond
((> pos span) #f) ; nothing was found thru the whole str
((not (char= c1 (string-ref str pos)))
(outer (+ 1 pos))) ; keep looking for the right beginning
((not (char= c2 (string-ref str (+ 1 pos))))
(outer (+ 1 pos))) ; could've done pos+2 if c1 == c2....
(else ; two char matched: high probability
; the rest will match too
(let inner ((pdx 2) (sdx (+ 2 pos)))
(if (>= pdx patlen) pos ; the whole pat matched
(if (char= (string-ref pat pdx)
(string-ref str sdx))
(inner (+ 1 pdx) (+ 1 sdx))
;; mismatch after partial match
(outer (+ 1 pos)))))))))
;@
(define (find-string-from-port? str <input-port> . max-no-char)
(set! max-no-char (if (null? max-no-char) #f (car max-no-char)))
(letrec
((no-chars-read 0)
(peeked? #f)
(my-peek-char ; Return a peeked char or #f
(lambda () (and (or (not (number? max-no-char))
(< no-chars-read max-no-char))
(let ((c (peek-char <input-port>)))
(cond (peeked? c)
((eof-object? c) #f)
((procedure? max-no-char)
(set! peeked? #t)
(if (max-no-char c) #f c))
((eqv? max-no-char c) #f)
(else c))))))
(next-char (lambda () (set! peeked? #f) (read-char <input-port>)
(set! no-chars-read (+ 1 no-chars-read))))
(match-1st-char ; of the string str
(lambda ()
(let ((c (my-peek-char)))
(and c
(begin (next-char)
(if (char=? c (string-ref str 0))
(match-other-chars 1)
(match-1st-char)))))))
;; There has been a partial match, up to the point pos-to-match
;; (for example, str[0] has been found in the stream)
;; Now look to see if str[pos-to-match] for would be found, too
(match-other-chars
(lambda (pos-to-match)
(if (>= pos-to-match (string-length str))
no-chars-read ; the entire string has matched
(let ((c (my-peek-char)))
(and c
(if (not (char=? c (string-ref str pos-to-match)))
(backtrack 1 pos-to-match)
(begin (next-char)
(match-other-chars (+ 1 pos-to-match)))))))))
;; There had been a partial match, but then a wrong char showed up.
;; Before discarding previously read (and matched) characters, we check
;; to see if there was some smaller partial match. Note, characters read
;; so far (which matter) are those of str[0..matched-substr-len - 1]
;; In other words, we will check to see if there is such i>0 that
;; substr(str,0,j) = substr(str,i,matched-substr-len)
;; where j=matched-substr-len - i
(backtrack
(lambda (i matched-substr-len)
(let ((j (- matched-substr-len i)))
(if (<= j 0)
;; backed off completely to the begining of str
(match-1st-char)
(let loop ((k 0))
(if (>= k j)
(match-other-chars j) ; there was indeed a shorter match
(if (char=? (string-ref str k)
(string-ref str (+ i k)))
(loop (+ 1 k))
(backtrack (+ 1 i) matched-substr-len))))))))
)
(match-1st-char)))
;@
(define (string-subst text old new . rest)
(define sub
(lambda (text)
(set! text
(cond ((equal? "" text) text)
((substring? old text)
=> (lambda (idx)
(string-append
(substring text 0 idx)
new
(sub (substring
text (+ idx (string-length old))
(string-length text))))))
(else text)))
(if (null? rest)
text
(apply string-subst text rest))))
(sub text))
;@
(define (count-newlines str)
(do ((idx (+ -1 (string-length str)) (+ -1 idx))
(cnt 0 (+ (if (eqv? #\newline (string-ref str idx)) 1 0) cnt)))
((<= idx 0) cnt)))
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