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The compileall script is used to compile to python bytecode all the modules.
However, it relies on the struct package that is not built for the host
python, thus crashing at execution when compiling the target python.
When compiling, the removed code block is never executed, so we can safely
remove it, removing in the same time the dependency on struct.
Patch by Maxime Ripard <ripard@archos.com>
Index: Python-2.7/Lib/compileall.py
===================================================================
--- Python-2.7.orig/Lib/compileall.py (révision 84276)
+++ Python-2.7/Lib/compileall.py (copie de travail)
@@ -14,7 +14,6 @@
import os
import sys
import py_compile
-import struct
import imp
__all__ = ["compile_dir","compile_file","compile_path"]
@@ -83,17 +82,6 @@
if os.path.isfile(fullname):
head, tail = name[:-3], name[-3:]
if tail == '.py':
- if not force:
- try:
- mtime = int(os.stat(fullname).st_mtime)
- expect = struct.pack('<4sl', imp.get_magic(), mtime)
- cfile = fullname + (__debug__ and 'c' or 'o')
- with open(cfile, 'rb') as chandle:
- actual = chandle.read(8)
- if expect == actual:
- return success
- except IOError:
- pass
if not quiet:
print 'Compiling', fullname, '...'
try:
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