From f5cb3cc89c0eb29347cdcb95dc6543f46af095d9 Mon Sep 17 00:00:00 2001
From: Opheliar99 <>
Date: Sun, 4 Jul 2010 04:11:13 +0000
Subject: posted solutions of 2 and 3 in pset2

---
 Problem Set 2.page | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Problem Set 2.page b/Problem Set 2.page
index 078d5e1..be65cd5 100644
--- a/Problem Set 2.page	
+++ b/Problem Set 2.page	
@@ -54,7 +54,7 @@ $a_{-4} = a_{4} = \sqrt{2\pi} \times 1/16$, $a_{-2} = a_{2} = - \sqrt{2\pi} \tim
 
 
 Since $a_m = < f_m, f >$,
-$\int_0^{2\pi} \sin^4(x) dx = <1, f> = \sqrt{2\pi} \times <f_0, f>$
+$\int_0^{2\pi} \sin^4(x) dx = <1, f> = \sqrt{2\pi} \times < f_0, f >$
 
 $= \sqrt{2\pi} \times a_0 = \frac{3 \pi}{4}$
 
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