From ec7c9f45428737bfe1afec1f977f7f2d517e25ed Mon Sep 17 00:00:00 2001
From: siveshs <siveshs@gmail.com>
Date: Fri, 2 Jul 2010 04:00:43 +0000
Subject: still testing

---
 Fourier Series.page | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Fourier Series.page b/Fourier Series.page
index 984f3e6..4ece8ea 100644
--- a/Fourier Series.page	
+++ b/Fourier Series.page	
@@ -38,7 +38,7 @@ Rearranging,
 $\qquad\sin^3(x) = \frac{3\sin(x)-\sin(3x)}{4}$  
 
 Substituting back in the former equation, we get  
-$\sin(2x).\cos(x) = 2 \sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}] $  
+$\sin(2x).\cos(x) = 2 \sin(x) - 2 [\frac{3\sin(x)-\sin(3x)}{4}]$  
   
 ##What is the Fourier series actually?</b>
 
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