From e3ddf20bf5077654ebfe90ada68c03b1314a1192 Mon Sep 17 00:00:00 2001 From: siveshs Date: Sat, 3 Jul 2010 05:31:14 +0000 Subject: editing --- Fourier Series.page | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/Fourier Series.page b/Fourier Series.page index 06e2d9b..bc1226d 100644 --- a/Fourier Series.page +++ b/Fourier Series.page @@ -13,7 +13,7 @@ We first begin with a few basic identities on the size of sets. Then, we will sh ## Proof that no. of available functions is greater than number of functions required to define the periodic function Consider any arbitrary periodic function in the interval $[-\pi,\pi]$. This can be represented as a series of values at various points in the interval. For example, -$\qquad f(0) = ... , f(0.1) = ..., f(0.2) = ... $ and so on. At each point, we can assign any real number (i.e. $\in \mathbb R$). So, the number of possible periodic functions in an interval is of the order of $\mathbb R^{\mathbb R}$. +$\qquad f(0) = ... , f(0.1) = ..., f(0.2) = ...$ and so on. At each point, we can assign any real number (i.e. $\in \mathbb R$). So, the number of possible periodic functions in an interval is of the order of $\mathbb R^{\mathbb R}$. --> don't quite remember how this goes. #Why Fourier decomposition is plausible? -- cgit v1.2.3