From 778d0aeb6e80b1653f0fcf042d76711fd4d49a0d Mon Sep 17 00:00:00 2001
From: Opheliar99 <>
Date: Sun, 4 Jul 2010 04:30:07 +0000
Subject: posted solutions of 2 and 3 in pset2

---
 Problem Set 2.page | 1 +
 1 file changed, 1 insertion(+)

diff --git a/Problem Set 2.page b/Problem Set 2.page
index de38296..ed138ec 100644
--- a/Problem Set 2.page	
+++ b/Problem Set 2.page	
@@ -44,6 +44,7 @@ $\sin x = \frac{e^{ix}-e^{-ix}}{2}$,
 $\sin^4 x = \frac{{( e^{ix}-e^{-ix} )}^4}{16}$
 $= \frac{e^{i 4x}+e^{-i 4x}-4 e^{i 2x} -4 e^{-i 2x}+6}{16}$.
 
+\\
 If we express any periodic function $f(x)$ as 
 
 $f(x) = \sum a_n f_n(x)$, where $f_n(x) = \frac{e^{inx}}{\sqrt{2\pi}}$ and $f_0(x) = \frac{1}{\sqrt{2\pi}}$,
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