From 37bad950149205dbc8a52f1b88d3a11911305859 Mon Sep 17 00:00:00 2001
From: Opheliar99 <>
Date: Mon, 5 Jul 2010 04:03:33 +0000
Subject: posted solutions of 2 and 3 in pset2

---
 Problem Set 2.page | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/Problem Set 2.page b/Problem Set 2.page
index d62036a..a6ed816 100644
--- a/Problem Set 2.page	
+++ b/Problem Set 2.page	
@@ -69,7 +69,7 @@ $$ \begin{array}{ccl} a_m &=& \frac{1}{\sqrt 2\pi} \int_0^{2\pi} \sin^2(x) e^{-i
 
 Because $\int_0^{2\pi} e^{inx} dx = 2\pi$ for $n = 0$ and $\int_0^{2\pi} e^{inx} dx = 0$ for $n \neq 0$, we have
 
-$$a_2 = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \sqrt{2\ pi}/4,$$
+$$a_2 = \frac{1}{4 \sqrt{2\pi}} \times 2\pi = \frac{\sqrt{2\pi}}{4},$$
 
 $$a_0 = \frac{1}{4 \sqrt{2\pi}} \times 2\pi \times (-2) = - \frac{\sqrt{2\pi}}{2},$$
 
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