From f0c461bce6678793f61c2e0c7fafd8b1801129f6 Mon Sep 17 00:00:00 2001
From: Opheliar99 <>
Date: Sun, 4 Jul 2010 04:12:42 +0000
Subject: posted solutions of 2 and 3 in pset2

---
 Problem Set 2.page | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

(limited to 'Problem Set 2.page')

diff --git a/Problem Set 2.page b/Problem Set 2.page
index 2d5a503..667abad 100644
--- a/Problem Set 2.page	
+++ b/Problem Set 2.page	
@@ -41,7 +41,6 @@ $\int_0^{2\pi} |\sin^2(x)|^2 dx = \sum |a_n|^2.$
 2. Since
 $\sin x = \frac{e^{ix}-e^{-ix}}{2}$,
 
-
 $\sin^4 x = \frac{{( e^{ix}-e^{-ix} )}^4}{16}$
 $= \frac{e^{i 4x}+e^{-i 4x}-4 e^{i 2x} -4 e^{-i 2x}+6}{16}$.
 
@@ -56,6 +55,7 @@ $a_{-4} = a_{4} = \sqrt{2\pi} \times 1/16$, $a_{-2} = a_{2} = - \sqrt{2\pi} \tim
 
 
 Since $a_m = < f_m, f >$,
+
 $\int_0^{2\pi} \sin^4(x) dx = <1, f> = \sqrt{2\pi} \times < f_0, f >$
 
 $= \sqrt{2\pi} \times a_0 = \frac{3 \pi}{4}$
-- 
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