From bd1a5eb91d0f8c5adfc4e3d71cb6ff992616713e Mon Sep 17 00:00:00 2001
From: Opheliar99 <>
Date: Sun, 4 Jul 2010 02:19:10 +0000
Subject: posted solutions of 2 and 3 in pset2

---
 Problem Set 2.page | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

(limited to 'Problem Set 2.page')

diff --git a/Problem Set 2.page b/Problem Set 2.page
index 518dccb..d001972 100644
--- a/Problem Set 2.page	
+++ b/Problem Set 2.page	
@@ -39,8 +39,8 @@ $\int_0^{2\pi} |\sin^2(x)|^2 dx = \sum |a_n|^2.$
 # Solutions
 
 2. Since
-$\sin(x) = \frac{\exp^{ix}-e^{-ix}}{2}$,
-$\int_0^{2\pi} \sin^4(x) dx = \frac{{e^{ix}-e^{-ix}}^4}{16}$,
+$\sin x = \frac{e^{ix}-e^{-ix}}{2}$,
+$\int_0^{2\pi} \sin^4(x) dx = \frac{{e^{ix}-e^{-ix}}^{4}}{16}$,
 $ = \frac{e^{i 4x}+e^{-i 4x}-4 e^{i 2x} -4 e^{-i 2x}+6}{16}$
 
 If we express any periodic function $f(x)$ as 
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