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authorluccul <luccul@gmail.com>2010-07-13 23:09:32 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-13 23:09:32 +0000
commiteccfe828cb03150e0e0db00616e1ab7c63afb7ce (patch)
tree5d5f31dc8eed7ea08ac935dad2dfc605ad837916
parenta71bb96bcc28e2cc09fb4b465f43933243fd9b2e (diff)
downloadafterklein-wiki-eccfe828cb03150e0e0db00616e1ab7c63afb7ce.tar.gz
afterklein-wiki-eccfe828cb03150e0e0db00616e1ab7c63afb7ce.zip
editing
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1 files changed, 1 insertions, 1 deletions
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@@ -26,7 +26,7 @@ First let's prove that $c_{-1}$ is zero. Since $c_{-1}$ is the residue of $f$ a
$$c_{-1} = \frac{1}{2 \pi i}\int_{\gamma_r} f(z) dz$$
where $\gamma$ is a small circle of radius $r$ that takes one counterclockwise turn around the origin. Taking the limit as $r \to 0$, we find ourselves integrating over a circle of radius $0$:
$$ c_{-1} = \frac{1}{2 \pi i} \lim_{r \to 0} \int_{\gamma_r} f(z) dz = \frac{1}{2 \pi i} \int_{\gamma_0} f(z) dz = \frac{1}{2 \pi i} \int_0^{2\pi} f(0) \frac{d\gamma_0}{dt} dt$$
-But $\gamma_0(t)$ is constant, hence $\frac{d \gamma_0}{dt} = 0$. Therefore,
+But $\gamma_0(t) = 0$, hence $\frac{d \gamma_0}{dt} = 0$. We conclude that
$$c_{-1} = \frac{1}{2 \pi i} \int_0^{2\pi} 0 dt = 0 $.
Now let's prove that $c_{-2}$ has to be zero. Consider the function