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authorluccul <luccul@gmail.com>2010-07-11 00:47:22 +0000
committerbnewbold <bnewbold@adelie.robocracy.org>2010-07-11 00:47:22 +0000
commit746e44533d73d61b2a9b63b11a2782fd1016bdc1 (patch)
tree1e7bee8b08e9c01ae745deec72863fcfff9c22b9
parent23dcf54d03c3b2e99e6fe68eb55ae15e4880479e (diff)
downloadafterklein-wiki-746e44533d73d61b2a9b63b11a2782fd1016bdc1.tar.gz
afterklein-wiki-746e44533d73d61b2a9b63b11a2782fd1016bdc1.zip
checking a formula
-rw-r--r--ClassJuly5.page5
1 files changed, 4 insertions, 1 deletions
diff --git a/ClassJuly5.page b/ClassJuly5.page
index 8a1ac2c..9af2b85 100644
--- a/ClassJuly5.page
+++ b/ClassJuly5.page
@@ -51,7 +51,7 @@ $$ a(t) = e^{-\lambda^2 t} $$
Next we solve for $b$. It satisfies the equation
-$$ \frac{d^2b}{dx^2} = -\lambda b $$
+$$ \frac{d^2b}{dx^2} = -\lambda^2 b $$
However we have to be a bit more careful in picking our solutions because $b$ is supposed to satisfy the boundary conditions
$$ b(0) = b(L) = 0$$
To satisfy $b(0) = 0$, we must take $b$ to be (a constant multiple of) a sine function:
@@ -73,3 +73,6 @@ In fact, every function of the kind described above does have a Fourier sine exp
How do we know that the Fourier series of a square wave or sawtooth function converges?
+The answer to this question depends greatly on the type of convergence desired. Aside from the convergence we already proved, the next easiest type of convergence is $L^2$ or root-mean-square convergence. The formal statement is that
+
+$$ \lim_{N \to \infty} \sqrt{\int_0^{2\pi} | \sum_{n = - N}^N c_n e^{in\theta} - f(\theta) |^2} = 0 $$ \ No newline at end of file